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J jahnavisub6 OFFICIAL
16 Aug 2026, 18:08

Clean Python solution, beats most submissions.

Use a hash map from value to index (or count). For each element check whether its complement is already in the map, then insert it. That makes it O(n) instead of the O(n²) brute force.

1 reply

mmishra 1 month, 3 weeks ago

You can avoid the extra array and do it in O(1) space.

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