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kavyanai4
28 May 2026, 15:14
Intuition + complexity breakdown for Reverse Bits.
XOR cancels equal numbers, and x & (x - 1) clears the lowest set bit. Both give O(1) space solutions here.
Intuition + complexity breakdown for Reverse Bits.
XOR cancels equal numbers, and x & (x - 1) clears the lowest set bit. Both give O(1) space solutions here.
Watch out for integer overflow in Java on the large test.
Watch out for integer overflow in Java on the large test.
Nice. Got asked a variant of this in an interview.
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