Problems / Count of Smaller Numbers After Self
Hard

Count of Smaller Numbers After Self

Hard 5 submissions 50 coins +200 XP
Binary Search Divide and Conquer Merge Sort
Problem Description
For each index `i`, count how many elements to the right of `i` are strictly smaller than `nums[i]`, and return those counts. **Example 1:** ``` Input: nums = [5, 2, 6, 1] Output: [2, 1, 1, 0] ``` **Example 2:** ``` Input: nums = [-1] Output: [0] ``` **Example 3:** ``` Input: nums = [-1, -1] Output: [0, 0] ```
Constraints
- `1 <= nums.length <= 10^5` - `-10^4 <= nums[i] <= 10^4`

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